it's getting there at least you can see that some are really trying to find the solution now
--> if you haven't figured it out yet --> there is a solution / a program for every puzzle on the internet, which also calculates such an easy task in seconds. who finds a good one can tell it to me with pleasure by pn, then I look at it;-)
criticism I gladly accept and improve it if necessary --> but that the opening text was written too incomprehensible?
partly I had to express it a bit complicated and confusing (otherwise too easy)
partly you have to read the text several times and think a little bit logically
and after my contribution above it suddenly went in the right direction
hint :
such results like 56487952 can never be correct, here again the text
--> your username must be included in your solution in the way that you add the individual valences of the letters / numbers to your result from the task above , only from m is equal to 1 is relevant here <--
note 2
no 4 digit numbers can come out even with long names and subtask 2 no cross sum is required.
--> now just concentrate only on your name and forget the variant and the checksum.
we make now simply a community project from it, have already written to a few of you who can tell me roughly their way of calculation by pn (if they want), then I see what it is and can give more appropriate hints in the forum.
--> would be laughed if not everyone finds an acceptable solution for themselves and writes here:D
another small lottery from gamble1 and me ;-)
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Huseyin, 
snopsim
--> if you haven't figured it out yet --> there is a solution / a program for every puzzle on the internet, which also calculates such an easy task in seconds. who finds a good one can tell it to me with pleasure by pn, then I look at it;-)
criticism I gladly accept and improve it if necessary --> but that the opening text was written too incomprehensible?
and after my contribution above it suddenly went in the right direction
hint :
such results like 56487952 can never be correct, here again the text
--> your username must be included in your solution in the way that you add the individual valences of the letters / numbers to your result from the task above , only from m is equal to 1 is relevant here <--
note 2
no 4 digit numbers can come out even with long names and subtask 2 no cross sum is required.
--> now just concentrate only on your name and forget the variant and the checksum.
we make now simply a community project from it, have already written to a few of you who can tell me roughly their way of calculation by pn (if they want), then I see what it is and can give more appropriate hints in the forum.
--> would be laughed if not everyone finds an acceptable solution for themselves and writes here:D
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another small lottery from gamble1 and me ;-)
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task2: 2290
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another small lottery from gamble1 and me ;-)
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Task 1 , Ergebniss 681, single digit checksum is 6
Task 2 including my name, result 711, even if the sum of the digits is not required, here it is anyway, it is 9
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another small lottery from gamble1 and me ;-)
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121
115
117
119
121
123
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another small lottery from gamble1 and me ;-)
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121
11675
11481
10987
10651
3825
3489
3019
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another small lottery from gamble1 and me ;-)
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Task 1: one-digit cross sum = 8
Task 2: 55
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another small lottery from gamble1 and me ;-)
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Task 1, one-digit cross sum is 6
Task 2, result is 36
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another small lottery from gamble1 and me ;-)
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Answer 1 / 8
Answer 2 / 79
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another small lottery from gamble1 and me ;-)
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If M is 1, do you stop at Z, or is A then necessarily the 15?
Thanks!
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another small lottery from gamble1 and me ;-)
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it shifts of course only the beginning. with a is counted then continuously further
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